Question 1073184
Sum of the interior angles of a trapezoid is 360 degrees.  Draw and label the points and angle measures. I assumed that side AR is parallel to side BN.  A key is that measure of interior angle at point R is {{{180-(3x-5)}}}.


Angle at R:
{{{-3x+175}}}



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The sum of the angles are A and B is also 180 degrees.
(Assumed AR parallel to BN)
{{{60+5x-15=180}}}
{{{5x=180-60+15}}}
{{{5x=135}}}
{{{highlight_green(x=27)}}}



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Angle at N:  76 degrees

Angle at R:  180-76=104 degrees
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