Question 1073291
Can use the normal approximation to this binomial.
np=mean which historically would be 38.42
np(1-p) is variance or 25.3572; sqrt is sd=5.036
a proportion of 0.15 represents 16.95
So z>=(16.95-38.42)/5.036=-4.26, which is about 100%.
------------------
z>(0.15-0.34)/sqrt((0.34*0.66)/113)=-0.19/0.0446, which is z>-4.26