Question 1073272
<pre>
(x-3)^2+(y+2)^2=9

Change the sign of the -3 to +3, or just 3

Change the sign of the +2 to -2.

Put those numbers in an ordered pair like this:

(3,-2)

That's the center of the circle

Plot it

{{{drawing(400,400,-1,7,-6,2, graph(400,400,-1,7,-6,2),

circle(43,-2,.07),circle(3,-2,.06),circle(3,-2,.05),circle(3,-2,.04),circle(3,-2,.03),circle(3,-2,.02),circle(3,-2,.01),locate(3,-2,"(3,-2)") )}}}

Now take the square root of  the 9 on the right side of
the given equation, 

(x-3)^2+(y+2)^2=9

and get 3.

That is the radius of the circle.  So open your compass
so that it is 3 units between the sharp point and the pencil.
Put the sharp point on the center (3,-2) and draw the circle:

{{{drawing(400,400,-1,7,-6,2, graph(400,400,-1,7,-6,2),
circle(3,-2,3),
circle(43,-2,.07),circle(3,-2,.06),circle(3,-2,.05),circle(3,-2,.04),circle(3,-2,.03),circle(3,-2,.02),circle(3,-2,.01),locate(3,-2,"(3,-2)") )}}}

That's the graph of

(x-3)^2+(y+2)^2=9

Edwin</pre>