Question 1073151
{{{y^2-4y-4x=0}}}
{{{4x=y^2-4y}}}
{{{4x=y^2-4y+4-4}}}
{{{4x=(y-2)^2-4}}}
{{{4x+4=(y-2)^2}}}
{{{highlight(4(x+1)=(y-2)^2)}}}


Vertex is the left-most point, and the parabola opens toward the right.  Symmetry axis is parallel to the x-axis.


Equation indicates vertex  (-1,2).


The factor 4 on the left indicates that some distance p so that 4p=4, is how far both the directrix and focus are from the vertex.  Here, p=1.  


DIRECTRIX:  {{{x=-2}}}
FOCUS:   (0,2)



{{{graph(300,300,-2,8,-3,7,2-2sqrt(x+1),2+2sqrt(x+1))}}}