Question 1073168
The area of the rectangle is {{{A[r]=6*2=12}}}{{{m^2}}}
The area of the semicircle is {{{A[s]=(pi/2)r^2=(pi/2)(3^2)=(9/2)pi}}}{{{m^2}}}
So together,
{{{A=12+(9/2)pi}}}{{{m^2}}}