Question 1072535
{{{ab(x^2-y^2)+(a^2-b^2)xy=0}}}
{{{abx^2-aby^2+a^2xy-b^2xy=0}}}
{{{a^2xy-aby^2+abx^2-b^2xy=0}}}
{{{(ay+bx)(ax-by)=0}}}
So then,
{{{ay+bx=0}}}
{{{ay=-bx}}}
{{{y=-(b/a)x}}}
and
{{{ax-by=0}}}
{{{by=ax}}}
{{{y=(a/b)x}}}