Question 1073134
{{{P=Fe^(rt)}}}
{{{800000=250000e^(0.08t)}}}
{{{e^(0.08t)=3.2}}}
{{{0.08t=ln(3.2)}}}
{{{t=ln(3.2)/0.08}}}
{{{t=(25/2)ln(3.2)}}}{{{years}}}