Question 1072890
Look at the possible outcomes, there are 36 of them starting with (1,1) and going to (6,6). The sums range from 2 to 12 with the following distribution,
2,1
3,2
4,3
5,4
6,5
7,6
8,5
9,4
10,3
11,2
12,1
So the number of outcomes greater than 9 is {{{3+2+1=6}}}
{{{P(A)=6/36=1/6}}}
Only the sum of 5 is divisible by 5, it occurs twice. {{{5+5=10}}} so then {{{36-10=26}}} of the outcomes are not divisible by 5.
{{{P(B)=26/36=13/18}}}