Question 1072813
{{{pi*R^2=50}}}
{{{R^2=50/pi}}}
{{{R=sqrt(50/pi)}}}
{{{C=2*pi*R}}}
{{{C=(2*pi)*(sqrt(50/pi))}}}
{{{C=2*sqrt(50pi)}}}
For a square,
{{{P=4s}}}
and
{{{A=s^2}}}
{{{A=(P/4)^2}}}
So,
{{{P=C}}}
{{{P=2sqrt(50pi)}}}
{{{p^2=4(50pi)}}}
{{{P^2=200pi}}}
and,
{{{A=P^2/16}}}
{{{A=(200pi)/16}}}
{{{highlight(A=(25pi)/2)}}}{{{m^2}}}