Question 1072718
The equation is separable.
{{{dy/sqrt(y)=dt/t^2}}}
Integrating both sides,
{{{2sqrt(y)=-1/t+C}}}
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So when {{{t=1}}}
{{{2sqrt(0)=-1/1+C}}}
{{{C-1=0}}}
{{{C=1}}}
{{{2sqrt(y)=-1/t+1}}}
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So when {{{t=1}}}
{{{2sqrt(1)=-1/1+C}}}
{{{C-1=2}}}
{{{C=3}}}
{{{2sqrt(y)=-1/t+3}}}