Question 1072776
Change-Base formula and rules for logs will give the system


{{{system(log(3,x)+2*log(3,y)=1,log(3,x)log(3,y)=-3)}}}


For temporary symbolic convenience, you can make substitutions for {{{log(3,x)}}} and {{{log(3,y)}}} and solve first in your new variables, and then back-substitute to continue.


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{{{system(log(3,y)=3/2,or,log(3,y)=-1)}}}
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{{{system(y=3^(3/2),or,y=1/3)}}}
.
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