<PRE><B>Question 94409</B>
Question:

The sum of two numbers is 112.  The second is 7 more than 4 times the first.  What are the two numbers?

Answer:


Assume that the first number = x


Four times the first number = 4x


7 more than four times the first = 4x + 7


Given that The second is 7 more than 4 times the first.....


So the second number  = 4x + 7


Their sum is given as 112



so we can write,


x + 4x + 7 = 112



==&gt; 5x + 7 = 112


Subtract 7 from both sides...



5x + 7 - 7 = 112 - 7



==&gt; 5x = 105


Divide both sides by 5


==&gt; {{{ 5x/5 = 105/5 }}}



==&gt; x = 21



So the first number is 21



Then the second number is 4x + 7 = 4 * 21 + 7 = 84 + 7 = 91


So the numbers are 91 and 21.


Hope you found the explanation useful.



Regards.


Praseena.





</PRE>