Question 1072507

Hello! I need help with the following question.
Graph the following parabola:
(x-3)^2=8(y+5). I only know how to find the vertex ( 3,5) and p which is 2. But I do not know how to find the focus and the directrix.
Thank you!
<pre>First of all, you have to determine whether the parabola has a vertical or horizontal axis.
This one has a vertical axis, so you compare the given equation to the standard-form equation, as follows:
{{{(x - 3)^2 = 8(y + 5)}}} ----- Given equation
{{{(x - h)^2 = 4p(y - k)}}} ----- Standard-form equation of a parabola with a vertical axis, with (h, k) being the vertex
You have the vertex, or (h, k) as (3, 5), but the vertex, or {{{highlight_green(matrix(1,5, "(h,", "k)", "=", "(3,", "- 5)"))}}}
As seen, 4p = 8, so {{{matrix(1,7, p, "=", 8/4, or, p, "=", 2)}}} 
Focus:     {{{highlight_green(matrix(1,5, "(h,", "k + p)", or, "(3,", "- 3)"))}}} 
Directrix: {{{highlight_green(matrix(1,11, y, "=", "k - p,", or, y, "=", "- 5 - 2,", or, y, "=", - 7))}}}