Question 1072522
 Help pls
Evaluate:

n(n-2)!/(n+1)!
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{{{ n((n-2)!)/(n+1)! }}} = 
{{{ n((n-2)!)/((n+1)(n)(n-1)(n-2)!) }}}
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The numerator is canceled by the two factors n*(n-2)! in the denominator, leaving:

{{{  1/((n+1)(n-1)) }}} =
{{{ highlight( 1/(n^2-1)) }}}