Question 94360
Q1 {{{slope=(m)=change in (y)/change in (x)}}}
in the equation 2x+3y=7 when y=0 x=7/2 (7/2,0) when x=0 y=7/3 (0,7/3)
{{{m=((7/3)-0)/((0-7)/2)=(7/3)*(-2/7)=-2/3}}}
the pependicular to m is {{{-1/m=(-1*3)/-2=3/2}}}
Q2  y=3x-1. 1st the intercepts. when y=0 3x=1 x=1/3 (1/3,0)
when x=0 y=-1 (0,-1)
{{{graph(500,500,-10,10,-10,10,3x-1)}}}
EdJones