Question 1072342
95% is +/-1.96 sd from the mean
That would be 0.000392 on each side of 5mm.
If I use 5.00000mm, then (4.9996, 5.0004) encompasses 95% of all diameters, assuming a normal distribution and a four place accuracy to the mean.
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The sample space has 12 items
H1---H6
T1---T6
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There are two possibilities BR, RB
(4/9)(5/8)+(5/9)(4/8)=40/72=(5/9)
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The total is 1
0.25 is 1
0.65 is another
That is 0.90
That leaves 0.10 probability for Andy.