Question 1072191
Let m be your first alloy, and n be your second. Then:
m+n=600
n=600-m
and
.35m+.5(600-m)=.45(600)
.35m+300-.5m=270
.15m=30
m=200 grams of the first alloy
600-m=400 grams of the second alloy. ☺☺☺☺