<PRE><B>Question 1072192</B>
I have a box of nickles and dimes. When I count the money, 
I notice that I have exactly $10, and that there are 144 
coins in the box. How many dimes and nickles are in the box?


&gt;&gt;... there are 144 coins in the box....&lt;&lt;
&lt;pre&gt;&lt;font size =4 color =&quot;indigo&quot;&gt;&lt;b&gt;
Translation:

(NUMBER OF NICKELS) 

plus 

(NUMBER OF DIMES)

equals

144

or   N + D = 144
&lt;/pre&gt;&lt;/font&gt;&lt;/b&gt;
&gt;&gt;... When I count the money, i notice that i have exactly $10...&lt;&lt;
&lt;pre&gt;&lt;font size =4 color =&quot;indigo&quot;&gt;&lt;b&gt;
Translation:

(5 cents times the NUMBER OF NICKELS) 

plus 

(10 cents times the NUMBER OF DIMES) 

equals

1000 cents  ($10 is 1000 cents 

or  5N + 10D = 1000

Solve this system by substitution or elimination  

{{{system(N+D=144, 5N+10D=1000)}}}

Answer: 88 NICKELS and 56 DIMES.

Edwin&lt;/pre&gt;  </PRE>