Question 1072074
The perimeter of a rectangle is 50m.  If the width were doubled and the length  increased by 19, the perimeter would be 108m.  What would the width of the rectangle. I need a formula please.
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There are two formulas:

2L+2W = 50   (1)
and
2(L+19) + 2(2W) = 108   (2)
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(2) simplifies to  2L+38 + 4W  = 108
                          2L + 4W = 70  (2')
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You can solve for L and W if you need to get their individual values.