Question 1071862
(8x^9y^3/27x^2y^12)^2/3
work inside
(8/27)^2/3*(x^7/y^9)^(2/3)
(4/9)*x^(14/3)/y^6; 8^2/3 is cube root of 8 squared; 27^2/3 is 9
(4/9)x^4*x^(2/3)/y^4