Question 1071838
he sum of 2 numbers is 20,
x + y = 20
y = -x+20
 their product is 10.
xy = 10
replace y with (-x+20)
x(-x+20) = 10
a quadratic equation
-x^2 + 20x - 10 = 0
using the quadratic formula, two solutions
x = 19.487, then y = .513 (subtract x from 20)
x = .513, then y = 19.487
:
the sum of their reciprocals is a,
a = {{{1/x}}} + {{{1/y}}}
a = {{{1/19.487}}} + {{{1/.513}}}
a = .0513 + 1.949
a = 2.00