Question 1071826
{{{((12x^(-4)y^3z^(-5))/(4x^4y^(-3)z^5))^(-2)=((12/4)x^(-4-4)y^(3-(-3))z^(-5-5))^(-2)}}}
{{{((12x^(-4)y^3z^(-5))/(4x^4y^(-3)z^5))^(-2)=(3x^(-8)y^(6)z^(-10))^(-2)}}}
{{{((12x^(-4)y^3z^(-5))/(4x^4y^(-3)z^5))^(-2)=(1/9)x^(16)y^(-12)z^(20)}}}
{{{((12x^(-4)y^3z^(-5))/(4x^4y^(-3)z^5))^(-2)=highlight((x^(16)z^(20))/(9y^12))}}}