Question 1071734
Find an equation of the line tangent to each curve through the given point

1. y=x2-3x+7 (2,5)
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Use ^ (Shift 6) for exponents.
It's a bad idea to include the problem #, 1. in this case.
Sometimes it is misconstrued as part of the problem.
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y=x^2-3x+7 (2,5)
y' = 2x - 3
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At x = 2, y' = 1, the slope of the tangent line.
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--> find an eqn of a line thru (2,5) with a slope of 1
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y - 5 = 1*(x - 2)
And we're done.