Question 1071597
An insurance company checks police records on 500 randomly selected auto accidents and notes that teenagers were at the wheel in 80 of them. Construct a 95% confidence interval estimate of the proportion of auto accidents that involve teenage drivers. Show all work. Just the answer, without supporting work, will receive no credit. 
-------------------
sample proportion:: 80/500 = 0.16
ME = 1.96*sqrt[0.16*0.84/500] = 0.0325
------------------
95%CI:: 0.16-0.0325 < p < 0.16+0.0325
-----
95%CI:: 0.1275 < p < 0.1925
----------------------
Cheers,
Stan H.
----------------------