Question 1070974
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Four roots, two are real, two are complex.
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{{{x-2}}} and {{{x+1}} are both factors of the polynomial,
{{{x=2}}} and {{{x=-1}}} are the two real roots of the equation,
{{{(x^4-x^3-x^2-x-2)/((x-2)(x+1))=x^2+1}}}
So the other two roots are 
{{{x=-i}}} and {{{x=i}}}