<PRE><B>Question 94305</B>
How many ounces of pure water must be added to 80oz. of a 35% salt solution to make a 14% salt solution?
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35% solution DATA;
Amt = 80 oz ; amt of salt = 0.35*80 = 28 oz
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Pure water DATA;
Amt = x oz ; amt of salt = 0
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14% solution DATA:
Amt = 80+x oz ; amt of salt = 0.14(80+x) = 11.2 + 0.14x oz
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EQUATION:
salt + salt = salt in mixture
28 + 0 = 11.2 + 0.14x
0.14x = 16.8
x = 120 oz (amount of pure water that must be added)
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Cheers,
Stan H.
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