Question 1071534
{{{2y=x-4}}}
{{{y=x/2-2}}}
The line perpendicular to this line going through (1,1) is,
{{{y-1=-2(x-1)}}}
{{{y-1=-2x+2}}}
{{{y=-2x+3}}}
Find the intersection of those two lines,
{{{-2x+3=x/2-2}}}
{{{-4x+6=x-4}}}
{{{-5x=-10}}}
{{{x=2}}}
Then,
{{{y=2/2-2}}}
{{{y=1-2}}}
{{{y=-1}}}
(2,-1)
So distance from (1,1) to (2,-1) is the same as the distance from (2,-1) to the symmetric point,
x:{{{2+(2-1)=2+1=3}}}
y:{{{-1+(-1-1)=-1-2=-3}}}
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*[illustration crt1.JPG].