Question 1071492
Let w be the speed at which Lynn walked.
Then 2w is the speed at which Lynn ran.

  (2hrs)(w mi/hr) + (45/60 hr)(2w mi/hr) = 14 mi

I'll drop the units while solving for w:
      2w + (45/60)(2w) = 14
      2w + 1.5w = 14
               3.5w = 14
                    w = 14/3.5 
                    w = 4  mi/hr   (her speed while walking)

This implies 2w = 8 mi/hr  (her speed while running)
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Ans:  Lynn walked at {{{ highlight(4) }}}mi/hr
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Check:    4mi/hr * 2hr + 8mi/hr*0.75hr = 8mi + 6mi = 14mi  (ok)