Question 1071467
{{{1&1/12}}} feet diameter wheel.


1 revolution is 1 circumference.
1 circumference is  {{{2*pi*(13/(2*12))=highlight_green((13/12)pi)}}} feet.


4 revolutions?
{{{cross(4*(13/6)pi)}}} feet
{{{4*(13/12)pi) feet
{{{cross(26pi/3)}}} feet.
{{{highlight((13/3)pi)}}} feet