Question 1071430
Factorable?  Discriminant, {{{(-2)^2-4*1*(-1)=4+4=8}}}.  Not really factorable.


Complete the Square to put into standard form.


{{{x^2-2x+1-1-1}}}
{{{(x-1)^2-2}}}
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{{{f(x)=(x-1)^2-2}}}------vertex is at  (1,-2).


Symmetry Axis:  at x=1.



Intercepts?
{{{(x-1)^2=2}}}
{{{x-1=0+- sqrt(2)}}}
{{{x=1+- sqrt(2)}}}
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You can also look for a y-intercept, by letting x=0 and evaluate y.  Find f(0).


ANSWER SUMMARY
Vertex (1,-2)
Axis Of Symmetry x=1
Roots  {{{1+- sqrt(2)}}}


{{{graph(300,300,-3,5,-5,3,x^2-2x-1)}}}