Question 1071338
We use the distance formula for two points
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Let PA be the distance from P to A = (3,2) and
PB be the distance from P to B = (-1,3) then
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PA^2 = (x-3)^2 + (y-2)^2
PB^2 = (x+1)^2 + (y-3)^2
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Also PA^2 = PB^2 / 2 or 2 * PA^2 = PB^2
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2 * [ (x-3)^2 + (y-2)^2 ] = (x+1)^2 + (y-3)^2
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2 * ( x^2-6x+9 + y^2-4y+4 ) = x^2+2x+1 + y^2-6y+9
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2x^2 -12x +18 +2y^2 -8y +8 = x^2 +2x +1 +y^2 -6y +9
:
x^2 -14x +y^2 -2y +16 = 0
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complete the squares
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1) (x-7)^2 + (y-1)^2 = -16 +50 = 34
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equation 1 is a circle whose center is (7, 1) and radius is the square root(34) or 5.831
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