Question 94264
(1st+2nd)(3rd-4th)
(x/3+3/4)(3x/4-3/5)
A.Multiply the 1st and 3rd terms {{{x/3*3x/4=x^2/4}}}
B.Multiply 1st & 4th and add it to the product of the 2nd & 3rd
{{{(x/3*-3/5)+(3/4*3x/4)=(-x/5)+(9x/16)}}}
The LCD is 16*5=80 {{{(-x/5)+(9x/16)=(-16x+45x)/80=29x/80}}}
C.Multiply the 2nd and 4th terms {{{3/4*-3/5=-9/20}}}
D.Add the results of A,B,C {{{x^2/4+29x/80-9/20}}}
E. It will look prettier with LCD of 80:
{{{(20x^2+29x-36)/80}}}
Ed Jones