Question 1071305

In the equation x^2-y^2=8 if the value of y=-1, the value of X is

A. -3
B. +3
C. +-3
     -
D. 9
<pre>All you need to do is just substitute - 1 for y
So, {{{matrix(1,5, x^2 - y^2 = 8, "becomes:", x^2 - (- 1)^2, "=", 8)}}}
Find x!
Why did you put x and X. It's one or the other as: {{{x <> X}}}.