Question 1071259
{{{y=ae^(bx)}}}
At {{{x=1}}},
{{{y=ae^b=2}}}
.
.
.
At {{{x=3}}},
{{{y=ae^(3b)=8}}}
So then,
{{{(ae^(3b))/(ae^(b))=8/2=4}}}
{{{e^(2b)=4}}}
{{{b=ln(2)}}}
So then,
{{{ae^(ln(2))=2}}}
{{{2a=2}}}
{{{a=1}}}
So,
{{{y=e^(ln(2)x)}}}
{{{highlight(y=2^x)}}}