Question 1071256
How far does Stacy get in {{{ 24 }}} min ?
{{{ d[1] = 6*( 24/60 ) }}}
{{{ d[1] = 24/10 }}}
{{{ d[1] = 2.4 }}} mi
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After {{{ 24 }}} min, they will be
{{{ 20 - 2.4 = 17.6 }}} mi apart,
and you start a stopwatch to 
measure time {{{ t }}} in hrs untill they meet
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Let {{{ d }}} = distance in miles Heather has
to walk utill they meet
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Heather's equation:
(1) {{{ d = 5t }}}
Stacy's equation:
(2) {{{ 17.6 - d = 6t }}}
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Plug (1) into (2)
(2) {{{ 17.6 - 5t = 6t }}}
(2) {{{ 11t = 17.6 }}}
(2) {{{ t = 1.6 }}} hrs
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In {{{ 1.6 }}} hrs, Heather has walked:
{{{ d = 5*1.6 }}}
{{{ d = 8 }}}
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Heather walked 8 miles from her original
destination until they meet
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check:
Stacy must have walked {{{ 17.6 - 8 = 9.6 }}} mi
{{{ 9.6 = 6*1.6 }}}
{{{ 9.6 = 9.6 }}}
So Stacy walked a total of {{{ 2.4 + 9.6 = 12 }}} mi
and added to Heather's distance,
{{{ 12 + 8 = 20 }}} mi
OK