Question 1071221
How can I solve the equation f(x)=2x^2-8x+2 through factoring?
<pre>{{{f(x) = 2x^2 - 8x + 2}}}
{{{matrix(1,3, y = 2x^2 - 8x + 2, or, 2x^2 - 8x + 2 = 0)}}}
{{{2(x^2 - 4x + 1) = 2(0)}}} =======> {{{x^2 - 4x + 1 = 0}}}
This equation cannot be solved through factoring since it requires a pair of factors with a product of + 1, and a sum of - 4.
Such INTEGER factors do not exist, and so, the equation's zeroes, or solutions MUST be determined by either using the quadratic equation formula: ({{{x = (- b +- sqrt(b^2 - 4ac))/(2a)}}}),
by COMPLETING the SQUARE, or by GRAPHING.