Question 1071223
X+2y=3,X-2y=3  

Y=2×-1,Y=3x-2

2y=6x-4,Y=3x-2

{{{system(X+2y=3,X-2y=3)}}}

{{{system(Y=2×-1,Y=3x-2)}}}----This one is not rendering.

{{{system(2y=6x-4,Y=3x-2)}}}


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Only doing one of your pair.
{{{system(2y=6x-4,y=3x-2)}}}


{{{2(3x-2)=6x-4}}}
{{{6x-4=6x-4}}}
redundant.


Why?
{{{2y=6x-4}}}---first equation of the pair
{{{2y(1/2)=(6x-4)(1/2)}}}
{{{y=3x-2}}}----same as second equation of the pair


The "pair" is really just one single equation in two different but equivalent forms.  Solutions form the line.