Question 1071122
In a survey of women in a certain country (ages 20-29) the mean height 63.7 inches with a standard deviations 2.65 inches. 
What is the height that represent 85 percentile ?
Find the z-value of the 85th percentile::
invNorm(0.85) = 1.0364
Find the corresponding height value::
h = z*s + u
h = 1.0364*2.65 + 63.7
h = 66.47"
---------------------------------
What is the height represent First quartile?
invNorm(0.25) = -0.6745
h = -0.6745*2.65+63.7 = 61.91"
Cheers,
Stan H.
--------