Question 1071157
	Tanya is considering playing a game at the fair. There are three different ones to choose from, and it costs $2 to play a game. The probabilities associated with the games are given in the table. 
Lose $2	Win $1	Win $4
Game 1	0.55	0.20 0.25
Expected "winnings" = 0.55(-2) + 0.2*1 + 0.25*4 = $0.1 = 10 cents
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I'll leave the others to you.
Cheers,
Stan H.
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Game 2	0.15 0.35 0.50 
Game 3	0.20 0.60	0.20 
a.	What is the expected value for playing each game?