Question 1071084
Its area WAS  6 SQUARE meters, {{{wL=6}}} with original w width and L length.


New area when enlarged,  {{{(L+3)(w+1)=3*wL}}}
{{{(L+3)(w+1)=3*6}}}
{{{(L+3)(w+1)=18}}}
{{{wL+3w+L+3=18}}}
{{{wL+3w+L=15}}}
{{{6+3w+L=15}}}
{{{highlight_green(3w+L=9)}}}
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Original area gives {{{L=6/w}}}.
Substituting for L in the "new area" equation gives  {{{highlight_green(3w+6/w=9)}}}.
Continue with this equation to find the value for w.
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