Question 1071028
Find the dimensions from the given perimeter and area.


{{{system(2w+2L=18,wL=20)}}}



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{{{system(w+L=9,wL=20)}}}

{{{L=9-w}}}
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{{{w(9-w)=20}}}
{{{-w^2+9w-20=0}}}
{{{w^2-9w+20=0}}}
{{{(w-4)(w-5)=0}}}


The way this situation works, one of the dimensions is 4 feet and the other dimension is 5 feet.  (If you were to first find w in terms of L and do the area formula substitution, you would have (L-4)(L-5)=0, so the same thing, same solutions - you might choose length as the bigger dimension.)