Question 1070865
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<pre>
  x^2p^2-8y^2p^2-4x^2q^2+32y^2q^2 =   (make grouping the terms)

= {{{(x^2p^2-8y^2p^2)}}} - {{{(4x^2q^2-32y^2q^2)}}} = 

= {{{(x^2 - 8y^2)*p^2}}} - {{{4(x^2-8y^2)*q^2}}} = 

= {{{(x^2-8y^2)*(p^2-4q^2)}}}.
</pre>

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