Question 1070830
-1/2x+2y"-13/2

You mean, {{{-(1/2)x+2y=13/2}}} ?
What is the slope?  Put into slope-intercept form if necessary.
{{{2y=x/2-13/2}}}
{{{y=x/4-13/4}}}
and slope of the given equation would be  {{{1/4}}}.


A line perpendicular to it would have slope  m so that {{{(1/4)*m=-1}}},
{{{m=-4}}}.


The line with this slope of {{{-4}}} passing through point (2,3) if put into the point-slope form is  {{{y-3=-4(x-2)}}}, 
and if wanted in the slope-intercept form,
{{{y=-4(x-2)+3}}}
{{{y=-4x+8+3}}}
{{{highlight(y=-4x+11)}}}-----line perpendicular to {{{-(1/2)x+2y=13/2}}} and containing point (2,3).



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In case your double-quote mark on the y was meant as "second derivative", then none of the above solution counts.