Question 1070768
{{{dm/dt+0.5m=15}}}
{{{m=Ce^(-0.5t)+15/0.5}}}
{{{m=Ce^(-0.5t)+30}}}
So when {{{t=0}}},
{{{C+30=A}}}
{{{C=A-30}}}
So,
{{{m(t)=(A-30)e^(-0.5t)+30}}}
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So depending on the value of A the function is either increasing or decreasing.

*[illustration mm.JPG].
Decreasing if {{{A>30}}}
Increasing if {{{A<30}}}
Constant if {{{A=30}}}
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As t gets large, {{{m(t)=30}}}