Question 94184
{{{log(2,(64))=x}}} Start with the given equation



{{{log(2,(2^6))=x}}} Rewrite {{{64}}} as {{{2^6}}}




{{{6*log(2,(2))=x}}} Rewrite the logarithm using the identity {{{log(b,(x^y))=y*log(b,(x))}}}



{{{6*(1)=x}}} Evaluate {{{log(2,(2))}}} to get 1  (note: {{{log(x,(x))=1}}})



{{{6=x}}} Multiply



So the answer is {{{x=6}}}