Question 1070674
{{{2x^2+2y^2+3x=0}}}


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{{{2x^2+3x+2y^2=0}}}
{{{2(x^2+(3/2)x)+2y^2=0}}}
{{{x^2+(3/2)x+y^2=0}}}, divided left and right by 2
{{{x^2+3x/2+(3/4)^2+y^2=(3/4)^2}}}
{{{highlight((x+3/4)^2+y^2=(3/4)^2)}}}


CENTER:  (-3/4,0)
RADIUS:  {{{3/4}}}