Question 1070540
<pre>
              SPEED      TIME     DISTANCE
TRAIN       *  6060        t         6060t
BUS            40        8-t       40(8-t)
Totals                    8          352
</pre>

Using variable t for the question asked, time on the train, just the distance sum should give the necessary equation:


{{{6060t+40(8-t)=352}}}


-
{{{6060t+320-40t=352}}}

{{{6020t=352-320}}}

{{{6060t=32}}}

{{{t=32/6060}}}

{{{t=0.00528*hours}}}------{{{0.318*minutes}}}, or 19 seconds.


-
*  Maybe a value in the problem description is wrong?  Maybe "60" mph was intended instead of 6060 mph?  In that case,
{{{60t+320-40t=352}}}
{{{20t=352=320}}}
{{{20t=32}}}
{{{t=32/20}}}
{{{highlight(t=96*MINUTES)}}} or 1.6 hours , or 1 hour 36 minutes