Question 1070491
Not completely clear.  Is it  3*log(2,(2+1))?
like this, {{{3*log(2,(2+1))}}}
?



{{{3*log(2,3)}}}

{{{log(2,3^2)}}}

{{{log(2,9)}}}


Applying Change of Base Formula,
{{{log(10,9)/log(10,2)}}}

{{{0.9542425/0.30103}}}

{{{3.1699}}}-----approximation