Question 94123
The given equations are:  


y = 9 - 3x  and x = 8 - 2y


The given equations are simultaneous equations and hence can be solved in this manner. 


3x = 9 - y  ---------------(1)

x = 8 - 2y  ---------------(2) 


Multiply eqn (1) by 2 and subtract if from eqn (2)



thus we get:  


6x = 18 - 2y 


x = 8 - 2y 
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5x = 10 


==> x = 10/5 


==> x = 2 


By back substitution, we get: y = 9 - 3x 


y = 9 - 6 


y = 3


Hence, the solution. 


Regards
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