Question 1070251
.
Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles. 
If Airplane 1 travels at 560 miles per hour and Airplane 2 travels at 570 miles per​ hour, how long into their flights 
will the two planes pass each​ other?

Thank you!
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<pre>
t = {{{565/(560+570)}}} = {{{565/1130}}} = 0.5 of an hour = 30 minutes.   (*)


The numerator 565 is the distance, in miles;

the denominator 560 + 570 = 1130 is the relative speed of the two planes, or the rate of decreasing the distance between them.


The formula (*) which I used is the standard formula  t = {{{distance/Rate}}}.
</pre>

On such problems, see the introductory lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A> 

in this site.


There is a bunch of lessons on Travel and Distance in this site.


See the online textbook 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.

under the topic "<U>Travel and distance</U>".